In I am a bit stuck. It's obvious f(x)' = 2 but the chain rule includes f(x)' applied to g(x) and g(x) = x², so why is there not an x² term in the derivative? It looks to me like it should be f'(g(x))g'(x) = 2(x²)2x. Where have I gone wrong following the formula? The actual calculation just looks like pulling out the constant 2 and using the simple power rule. I am confused about where the chain rule actually comes into this calculation.(00:03:25 - 00:05:29)
Backpropagation in 5 Minutes (tutorial)
Siraj Raval
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